Hello to all.
If anybody can help me to find the solution.
I am doing research on the energy balance of the earth. I started using FLIR A305sc to determine the temperature of the surface of plant at long range.
About Planck R canstant.
With ExiftoolGUI I get:
Planck R1 : 16314.8828125
Planck B : 1423.59997558594
Planck F : 1
Planck O : -6199
Planck R2 : 0.0109910489991307
Peack of spactral range 10.11 mkm
For have a proof, I calculated:
B = h*c/(k*?)=(6.626068*10^-34*2.9979*10^8)/(1.38066*10^-23*10.11*10^-6) = 1423 (Planck B)
R=R1/R2=1.484*10^6, so...
R = 2*h*c^2/?^5=(2* 6.626068*10^-34*(2.9979*10^8)^2)/(10.11*10^-6)^5 = 1.128*10^9
? why not 1.484*10^6
And another question.
If spectral range is a constant (10.11 micromètre) then Wien law of displacement (lambda=2898/T) is not provided in FLIR???
Thank you in advance for yours reply.