Interesting point, I've never noticed that before.
But it's quite obvious, how to interprete this.
A good description of the instrument is in the April 1989 HP journal.
My values are those:
CAL? 1,0 = 40,0000000E03 (default value)
CAL? 1,1 = 40,0000000E03 (actual value = cal value)
CAL? 1,0 = 40,0800000E03 (max. actual value)
CAL? 1,0 = 39,9200000E03 (min. actual value)
CAL? 2,0 = 7,20000000E03 (default value)
CAL? 2,1 = 7,20509364E03 (actual value = cal value)
CAL? 2,0 = 7,50000000E03 (max. actual value)
CAL? 2,0 = 7,00000000E03 (min. actual value)
The x,1 values are the real values of the references, which are determined during 10V / 10 kOhm artefact calibration. That means, you unsecure the cal mode, apply an exactly known reference as 10,000050 V or .. kOhm from external standards (732B / ESI SR104), and type in the exactly known value. See calibration manual.
The 3458A then compares very precisely the internal reference against the external standard and calculates, which voltage or resistance values its internal references have, actually.
This calibration constant x,1 is stored in non volatile memory and used afterwards for each measurement.
If the calibration memory is lost, the default values are used, i.e. 40,0 kOhm and 7,2V.
The internal reference components, that is a Vishay hermetical sealed metal foil resistor, and the Linear LTZ1000A, have a specified tolerance, i.e. min. and max. values.
Those limits were checked during the calibration process.
If the calculated actual value is outside the limits, the components may be faulty, and perhaps the calibration is not accepted, i.e. an error occurs.
The 40k resistor may vary obviously +/- 0.2%. In the CLIP, it's specified 0.1% / 1.3ppm/K, so the limit of 0.2% is wide enough for all possible temperature variations of the reference resistor, i.e. up to 80°C.
Similarly, the LTZ1000A is specified in the LT datasheet 7.0 - 7.2 - 7.5V @ 5mA, so that's exactly what HP has programmed into the 3458A.
If your actual 40k value 1,1 is corrupted, i.e. outside the limits, your cal memory may be defective. During normal operation, there may be no check on that.
Anyhow, then you should already have gotten CAL RAM errors.
If you send in such an instrument, agilent will for sure repair the CAL MEM, by completely updating the PCB (additional 1000 bucks or so).
It's possible to repair that on your own before sending to agilent, look for the numerous threads here and at other places.
PS: Would be nice that you publish your x,1 constants here, so that the situation is clear for the reader also.
And your final findings - would be nice if you post that too, as a feedback.
Frank