A person had posted the attached bone to pick with me after posting my last video. This is in regards to my cutting open the HRC fuse. I've attempted to look at the clearance and creepage for the current inputs before. I don't have a 500VA supply as the standard calls for but I am really just interested in seeing if anything starts to breakdown at the 2X level. In the case of the 87V, I really don't like that sleeved battery wires running between the fuse holders, however at least at 2KV it does not seem to have a problem with it.
That said, one comment they made I found of interest:
You performed a completely useless test by emptying the fuse out. It's simulating a fault which would not exist. In the field you either have an intact fuse, or a blown one.
Does a fuse really only have two state? For fun, if I take say an inch of some 30 AWG wire and connect it to my 20A power supply, then slowly increase the current until the wire opens you may find that the point where it breaks that the wires are still very close to one another. This is how I opened up the fuse that I used for these tests and when I cut open the fuse, the filament was still mostly there. No molten filler and such. So when I attempted to apply a few KV to it, it would light up.
Had I connected this same fuse to my half cycle simulator, I suspect there would be nothing left of the filament and the fuse would not have broke over at the 2KV test voltage. I've made a few videos showing various fuses being blown with various levels of energy. I doubt anyone here would believe connecting my fuse powered rocket to a 100A, 2V power supply would get it to lift off. It may actually be possible to get it to be an open to the 2V supply but still be able to launch. Similar to how I test the meters, if I apply a 5KV pulse and it arcs over, then feed the energy from the half cycle simulator into it.... Well, maybe.
Anyway, I don't believe there are just two states.
https://youtu.be/xLDok9Sm07Q?t=117