I have a radio that I'm attempting to repair, a Roberts Classic 927 (model no. R9927). Apparently, while it was on (I wasn't there at the time), something went 'fizz/crackle' and it just stopped working.
Suspecting that something like an electrolytic capacitor had popped, I opened it up, but couldn't see anything that looked bad. This radio can be powered either from mains AC or from batteries (4x 1.5V = 6V), so suspecting that perhaps it may be something with the mains power supply, I tried hooking up the battery terminals to my bench PSU and gave it 6V. It works!
So, something is wrong with the mains power supply. I began to trace the circuitry, but I am puzzled as to why it is built like it is, and how it failed.
As far as I could determine, the mains power circuit is as follows:
The mains AC comes in via a 2-pin figure-8 connector and goes straight to a small transformer. The transformer has 3 wires out: middle one goes to circuit ground, the other two both each go to a series rectification diode (with parallel ceramic cap), which are then commoned together and smoothed by an electrolytic and small ceramic cap. This DC power then goes to a switch integrated into the AC socket, which appears to be used to switch out the battery power when AC is plugged in.
I am confused as to why they are using the transformer like this.
Can anyone explain?
From what I can determine, the transformer is at fault. When powered, there is zero voltage on the secondary side. If I measure the resistance of the windings, on the secondary I get 3.5 ohms between the 'ground' tap and each other one. The primary side appears to be open-circuit. The transformer has a label on it stating has a thermal fuse, but there is no sign of overheating whatsoever. Are thermal fuses typically on the primary side? If that has broken, that would explain the open-circuit measurement.
Don't know whether I should bother looking for a replacement transformer, or just bodge a DC barrel jack into the thing and rewire it to run off of that.