Pleas disassemble your TDS540C w 1G Option and pick A10 Board out.
Pleas read Service Manual for 500C/700C Series. It is much step for disassemble to resistor-ID
4x ID-resisistor is on bottom of A10 Acquisition board.
Location: near 4 golden koax connector to rear BNC connector. Then pleas flip it to bottom , you'll found only one 0 Ohm Resistor on R1061. Added two 0 Ohm Resistor to R1062 & R1063
Pic show top-layer of TDS520C/TDS724C A10 Board, location of ID-resistor (of coruse, it is on other layer)
Hello Madao,
This sunny day morning, I deconstruct the acquisition board of the TDS540C-1G unit per your instructions to find the 4 resistors in charge to allocate 1G 2G, please see attached picture.
Indeed there is 0R resistor for R1061 where the 3 other resistors R1062 R1063 and R1064 are open
If I add two 0 Ohm Resistor to R1062 & R1063, do I need to leave 0R on R1061 to enable standard option 2G ?
By the way, what is the role of R1064 or more generally, what are the meaning of all combinations of R1061 R1062 R1063 and R1064 ?
If I make the 2G modification, do I need to recalibrate the unit ?
Do you know if upon starting - booting the TDS540C will automatically remove the 1G display and there is no need to remove the 1G option by software ?
Last question, the zoning of R1061 to R1064 shows two IC, these are X24C02 under U1055 and U1052. Are these ICs the EEPROM keeping the factory calibration constant and does firmware update could write-change their content ?
Thanks, Albert