On that page you linked, you'll notice the asymmetrical current of the positive and negative outputs (700mA for positive, 150mA for negative) that tells me the output is from a charge pump, driven by the switching node. Its quite a common way to add a negative rail to a boost converter, as it only really requires two diodes and two caps, with an output of roughly the positive rail -2Vf where Vf is the forward bias drop of the diodes used, ~0.3V for shottky, and ~0.65V for silicon.
It'll have an output resistance much higher than the positive rail, and won't be tightly regulate... so if you pull say 50mA from it, and your positive rail is set to 12V, you won't get -12V more like -9 (all depends!).
But for low currents, its a fairly simple and clean way to get a negative voltage form a boost converter. At that price I don't think it will hurt to get one and test it.
So, the short answer is, "charge pump", with an output of -12V - 2*-0.3V = -11.4V.
Edit: fixed typo's, because otherwise I can't sleep!