Author Topic: how does this circuit works?  (Read 1019 times)

0 Members and 1 Guest are viewing this topic.

Offline Danesh_SATopic starter

  • Contributor
  • Posts: 30
  • Country: us
how does this circuit works?
« on: December 21, 2019, 08:11:41 am »
Hi All,
Im on a isolated digital output circuit,i found this circuit.could you expain me how it works? what does BAV70 do here?
 
The following users thanked this post: Paul Ed

Offline erikka

  • Regular Contributor
  • *
  • Posts: 190
  • Country: nl
Re: how does this circuit works?
« Reply #1 on: December 21, 2019, 08:43:55 am »
See equivalent circuit of each driver
The diodes are to clamp the output between GND and Vcc
 
The following users thanked this post: Paul Ed

Offline Danesh_SATopic starter

  • Contributor
  • Posts: 30
  • Country: us
Re: how does this circuit works?
« Reply #2 on: December 23, 2019, 03:10:06 pm »
I design 4 channel digital output for industrial system ,I want to use ULN2803 instead of TBD62783 in my design.
but don't understand the usage of BAV70 here,this is DIGITAL OUTPUT ,why in this design use CLAMP diodes?
 

Offline awallin

  • Frequent Contributor
  • **
  • Posts: 694
Re: how does this circuit works?
« Reply #3 on: December 23, 2019, 03:19:12 pm »
if you have inductive loads (relays) they might give enough 'kick' to damage the driver, without protecting diodes?
 
The following users thanked this post: Danesh_SA

Offline PKTKS

  • Super Contributor
  • ***
  • Posts: 1766
  • Country: br
Re: how does this circuit works?
« Reply #4 on: December 23, 2019, 03:19:43 pm »
(..)
but don't understand the usage of BAV70 here,this is DIGITAL OUTPUT ,why in this design use CLAMP diodes?

ESD or worst spikes
 

Offline rstofer

  • Super Contributor
  • ***
  • Posts: 9931
  • Country: us
Re: how does this circuit works?
« Reply #5 on: December 23, 2019, 03:38:44 pm »
To prevent the signal lines from going above Vcc by more than a diode drop.  This protects the chip inputs (or outputs, in this case).  It doesn't matter WHY the signal line goes above VCC (ESD, whatever), it is necessary to protect the chip.

Given that each output is also fused, we can assume it is intended to protect the device from miswiring.  Inductive kickback is handled inside the driver chip for the case where the output goes below ground.  These external diodes clamp when the output is somehow pulled above Vcc.

« Last Edit: December 23, 2019, 06:29:39 pm by rstofer »
 
The following users thanked this post: Danesh_SA

Offline Danesh_SATopic starter

  • Contributor
  • Posts: 30
  • Country: us
Re: how does this circuit works?
« Reply #6 on: December 23, 2019, 09:39:14 pm »
These external diodes clamp when the output is somehow pulled above Vcc.

Thank you for detail answer.now i find out how it works,but still can't understand how BAV70 works in output mode!
I think it prevent damege to chip when we use it as INPUT ,which is wrong and these diodes to prevent from failing.
I have this ideas but I don't know do I think in right way?!

 


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf