Author Topic: Transconductance opamp set up as "Voltage follower"?....Boost PFC battery charge  (Read 625 times)

0 Members and 1 Guest are viewing this topic.

Offline ocsetTopic starter

  • Super Contributor
  • ***
  • !
  • Posts: 1516
  • Country: 00
Hello,
We have special batteries which are pretty much always 400V +/-5V no matter what  the state of charge.
We want to charge them with  a  non isolated  “controlled  open loop” BCM Boost PFC converter as attached. (we’ll be careful). PDF schem and LTspice sim as attached.

This involves setting up the internal transconductance error amplifier in an LT3799 (Boost BCM PFC)  IC  as a simple buffer as shown...
Then one simply adjusts the charge current by adjusting the voltage into the CTRL3 pin of the LT3799 controller as  shown. (“iterative set and check algorithm”)

Can you see any problems with this? That is, the connection of the internal transconductance opamp as a "voltage follower"  as shown.

Datasheet:   LT3799 BCM Boost PFC controller IC
https://www.analog.com/en/products/lt3799.html
 

Offline NiHaoMike

  • Super Contributor
  • ***
  • Posts: 9164
  • Country: us
  • "Don't turn it on - Take it apart!"
    • Facebook Page
You still want voltage feedback as a failsafe mechanism to stop charging. Actually, you'll want several of those mechanisms since such a large battery can fail in a very dramatic way.
Cryptocurrency has taught me to love math and at the same time be baffled by it.

Cryptocurrency lesson 0: Altcoins and Bitcoin are not the same thing.
 
The following users thanked this post: ocset

Offline ocsetTopic starter

  • Super Contributor
  • ***
  • !
  • Posts: 1516
  • Country: 00
Thanks, yes...we will have a FET switch in series with that battery (not shown in top post) , and if its voltage goes too high, we'll switch it out.

Do you think maybe we'll need to connect inputs and output of the OTA together, then apply the control voltage to that? (instead of the way we've done it in the top post)?
After all, if inputs of OTA are the same, then its output current is zero...and so its output impedance must then be highest, which is probably  good for our situation where we want to "Inflict" an external voltage onto the OTA output? (in order to control the power throughput of the Boost PFC stage)
« Last Edit: June 16, 2020, 10:29:15 am by treez »
 

Offline David Hess

  • Super Contributor
  • ***
  • Posts: 16976
  • Country: us
  • DavidH
It should work but I suspect there are better ways albeit probably not as inexpensive.

Thanks, yes...we will have a FET switch in series with that battery (not shown in top post) , and if its voltage goes too high, we'll switch it out.

That is going to be a problem.  Protection against open circuit faults require the output to conduct 2% of the output current which is done with some type of shunt, like a zener diode.

Quote
Do you think maybe we'll need to connect inputs and output of the OTA together, then apply the control voltage to that? (instead of the way we've done it in the top post)?
After all, if inputs of OTA are the same, then its output current is zero...and so its output impedance must then be highest, which is probably  good for our situation where we want to "Inflict" an external voltage onto the OTA output? (in order to control the power throughput of the Boost PFC stage)

The application notes show the control inputs connected to the positive reference to disable them but I do not see where it matters.

 
The following users thanked this post: ocset


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf