Sure. Polymer values are much smaller; have you checked what ripple voltage would be at that frequency?
This brings dielectric loss into play. Dielectric loss looks like an R+C in parallel with the main C, with the extra C being small (about tan 𝛿 times main C).
Or if you stick with ESR (being equivalent series resistance), the ESR rises at low frequencies.
So the key is that the ripple voltage rises at low frequencies, while the Q factor stays roughly constant (Q ~= 1 / tan 𝛿).
Knowing Q factor, you can calculate loss. Find the reactive power, then multiply by tan 𝛿 to get the real power (loss). Reactive power is V*I (more or less), so once you know ripple and capacitance, you know this.
Tim