It definately does matter when you're trying to meet conducted EMI requirements and your switches and drive circuit are attached to the chassis. The circuit has 3 phase legs, with high side bootstrapped switches. So the isolator, votlage regulator circuit and FET driver circuit are seeing the 25V/ns and are also sitting on the chassis. We're using a Si8233 which uses capactive coupling over the isolation barrier, it's rated at 45kV/us. I am aware of the the ADuM series, but they weren't usable for us.
Yikes, that much dV/dt for a mere motor driver?! I hope you're running at high frequency (>200kHz?) and filtering heavily (but hey, filtering means low EMI, so that's good).
Everything going to chassis is a good thing, so long as you can attenuate all the escape paths for noise. Lots of Y caps and CMCs, that kind of thing. For both input and output sides.
And your problem was probably a bit different, these switches have little capacitance around 100pF (650V 30A device). In fact we had to externally increase the Cgs to allow a reduction in Rg to prevent the opposite switch turning on during the driven switches transition (due to miller capacitance).
Yes, my case the transistors were big old VDMOS. But don't have any illusions: yours are likely *just* as bad, at certain conditions. I'm guessing those are SuperJunction type? (Even if they don't use that term in the datasheet, you can tell because the Crss, Coss vs. Vds drops precipitously around 20-50V, and remains very low (~pF) or even rises slightly, in the >100V range.) The difficulty there is, when one side turns on, it has to charge the opposite side capacitance, which looks like reverse recovery because it's such a massive capacitance (~nF) for low voltages. The charge (Qd) still may not be much, but because it's charged through a huge fraction of Vdd (<50V Vds means the other transistor was dropping, what, 300V+ during that 'recovery' phase?), the switching losses can still be just as large as with VDMOS.
If your load is inductive, and you can afford to wait the dead time for the reactive current to commutate the inverter voltage, you get ZVS with almost zero switching loss. Unfortunately, few real circuits (like motor controllers and inverters) have such a load characteristic in general, so it's something you can only take advantage of when given the opportunity...
Tim