No; get STP that's rated, if possible. Or measure it.
The figure-eight geometry of the shield (or maybe it's more elliptical, depends!) isn't anything I know of a solution for. Maybe it has been done, but it's a pretty special case.
Do think I've seen or heard of differential coax, that is, two round wires inside a circular shield. Might be a calculator or formula for that.
You can always calculate it numerically; ideally a proper field solver is used, but a 2D electrostatic solver like ATLC2 can get approximate results (the result is correct, given the input geometry, but what's missing is the dynamics: the skin effect and loss of the wire and dielectric, dispersion (change in velocity factor versus frequency), etc.).
But anyway, that's a lot more work than is necessary here -- it's going to be somewhere around 70 ohms for STP and 100 ohms for UTP. Just based on the materials and dimensional ratios of commercial pair. Better than 20% matching really isn't necessary.
Yeah, caps probably over 1nF is a good idea, 10 or 100nF is fine.
Also, if the remote device is itself isolated from ground, no need to isolate the shield, just tie everything in. So, uh, that thing's not in a metal structure, right? All wood and composite or what have you? Yeah, you're making your own grounding circuit then. Run power in parallel (same harness and routing), can use the shield for ground return most likely so you only need three wires (VCC, CANH, CANL) and the shield.
Which, can be multiconductor cable once again -- if the VCC wire were, say, bypassed to ground at both ends with capacitors, it would act somewhat like another ground conductor, so your braided multiconductor cable looks suspiciously like braided STP once again, and the same impedance assumption applies.
This breaks down when the cable length is 1/2 wave resonant with the signal, where the VCC line will get some resonant voltage in the middle, and currents at the ends. There's not really any need for VCC to be hard bypassed -- that was just an illustration. A ferrite bead at each end (on just VCC) might be better, absorbing any energy coupled to it. Which, is only coupled from the signals in common mode anyway, so we don't expect that to be a large noise source in the first place, and we don't have any qualms about sinking energy from it (we won't dramatically increase differential signal losses or anything).
BTW, note that ferrite beads saturate easily with current, for example a 100 ohm (at 100MHz) 1206 chip bead might be rated for 2A DC, but its impedance falls by 3dB at merely 100mA DC bias. These curves can be hard to find (Laird is one brand which does provide them, for almost every part in their catalog). If you need more current, just use an inductor -- which saturates at a known given current. The lossiness of the ferrite bead can be emulated with an R or R+L in parallel with the inductor, or an R+C across the connection (VCC to GND).
And then, maybe a TVS from GND to VCC, for example a SMAJ15A or P6KE15A for a 12V bus*, will keep the peak voltage to say 20V or so, even under conditions of inrush, surge, ESD, etc., and that covers pretty much everything you'd want for EMC purposes, both power and signal (as discussed earlier).
*Assuming battery powered conditions. If this is supplied by alternator, there is a chance of load dump, which is when the battery comes disconnected while the alternator is delivering heavy charge current. The alternator can't reduce its output that quickly, so the excess energy goes into the system. Typical waveforms are (for 12V bus), 60V peak, 3ms rise time and 100ms fall time (decaying exponential shape), 2 ohms source impedance. So, 60V from 2 ohms is quite a lot of peak power if you were unlucky enough to absorb it all at once. There are many mitigation options available from the automotive world.
Tim