Hello,
I've got a question for ya. It may sound stupid at first glance, because I know generally high powered LEDs are run with a heat sink. But in my application I'm space constrained and even if I wanted to, I don't know how I'd attach a heat sink, with nothing but the LED itself to attach it to and with the pads so close to the mounting holes that the head of any screw would surely contact them.
So the LED I want to drive is this one:
http://www.digikey.com/product-detail/en/XMLCTW-A0-0000-00C3ABB02/XMLCTW-A0-0000-00C3ABB02CT-ND/3711461As you can see it's expensive. So I don't want to blow it up.
Now, the LED is rated for up to 1A per die, which I assume means per color. But I don't want to run it that high. I've found a simple way to drive each color at up to 250mA. I could limit it to 150mA but I'd prefer not to go below that.
Futhermore, I will likely be lighting only two colors at a time. On top of that, I will be flashing the LEDs and/or fading them in and out, so they would be on around 50% of the time. In other words, if you calculate the total power dissipation for all four colors running @ 250mA each, then in actual usage, the power that needs to be dissipated would be more like 25% of that.
That said, for simplicity's sake, I'd like like to know, if I have all four dies lit at once, what current would I need to limit each one to in order to keep the LED's junction temperature from exceeding, say 100 degrees?
I found this nice calculator:
http://support.luxeonstar.com/customer/portal/articles/179490-how-do-i-determine-what-size-of-heat-sink-i-need-includes-heat-sink-calculator-But it wants me to input data for the heat sink which doesn't exist.
I put in the following values:
Vf = 3.9 (worst case)
I = 250mA
LEDs = 1 (can't change this, so if I want to calculate more than one die on at a time I'd just multiple the current by 4)
And that gives Watts = 1
So if I had two of the dies on at once, it would be 2 watts. But let's just continue with 1 for now.
Now I get to the thermal calculations...
Maximum Junction Temp = 100C
Junction to Thermal Pad = 3.5 (that's what the datasheet says anyway)
LED mounting base = 6 (I looked all over the place for information on what the termal resistance of these aluminum PCBs was but the numbers were all over the place from 2W/m-K to 150W/m-K, and that's not even C/W and I have no idea how to convert it or if it is even the same thing, but C/W was listed nowhere, so I just assume the default value of 6 is good here.)
Heatsink attachment = I just left this at the default of 4.5
Ambient Temp = 25 (again just left it the default)
And then I click calculate and it tells me...
Maximum Heat Sink Thermal Resistance = 62.9C/W
Okay... So just for a sanity check I increased the LED current, and that value goes down. So down means the heat sink needs to be better.
But wait.. My PCB has a thermal resistance of 6C/W. That's better than what they say the heat sink has to be. So what gives?
Are they making some assumption about the size of the heat sink? Or is the PCB in fact good enough as a heat sink when powering a single die with 250mA?
If I put in 1000mA, to simulate all 4 leds being on at once and driven with 250mA, I get 5.2C/W.
Except that forward voltage I used was the worst case for the green die. If I average all the maximum forward voltages instead, I get 3.475V. And if I put that in instead, then the heat sink calculation rises to 7.6C/W.
But wait again. That thermal pad conduction... Is that affecting the calculation? Well, I have no thermal pad, since I have no heat sink. So maybe I should set that to 0? If I do that then the heat sink value rises to 12C/W.
Am I on the right track here? I kinda doubt it. I'd be surprised if I can drive 1A constantly into this LED (250mA per die) with no heat sink and only get what I assume would be a 50C rise (since the thermal caluclation says the heat sink only needs to be 12C/W but the PCB is 6C/W and I wa calculating for a 100C rise)