thanks alot for the input andreas
i am unsure how you make the 3/7 or 1.5/3.5 ratio with 8 equal value resistors ?
please explain ?
naked chip, value does not matter, it is all about ratios:
1 1 1 1 1 1 1 1
use two of them in parallel
1 1||1 1 1 1 1||1
gives
1 0,5 1 1 1 0,5
switch them in series:
1-0,5 1-1-1-0,5
gives
1,5 and 3,5
total is 5
3,5/5=0,7
7V / 0,7 = 10V.
But honestly, what improvement do you expect over a simply solution with two resistors?
Are you able to estimate that in quantitative terms or even measure it?
Using that TDP1603 Andreas mentioned could be considered overkill (but it is an already much cheaper solution compared to what was promoted years ago here...).
You might even try out 8x 2,2kOhm resistors in metal film quality.
Real voltnuts obviously only use hermetically sealed custom-built Vishay VHP dividers at the cost of the GDP of Nicaragua.
Another possibility is to use custom-built wirewound precision resistors, wound by virgins at full-moon in leap years.
But if it makes you feel good throw in all the expensive stuff.
![Wink ;)](https://www.eevblog.com/forum/Smileys/default/wink.gif)
Regards
try
P.S.: You can try out an arrangement that takes into account heat distribution because the two paralleled ones are running with half the current: P= (I/2)^2*R = 0,25*I^2*R compared to I^2*R for one single resistor. But with larger resistor values it won't matter anyway.