Help deciphering ts5a23159 power off state

[oliv3r]

Hey all.

I'm trying trying to understand what the [TS5a23159](http://www.ti.com/lit/ds/symlink/ts5a23159.pdf) does when no voltage is present on VCC (VCC < 0.1).

The datasheet has only one image really talking about the 'PWROFF' state, Figure 15 (attached). Which somehow ironically seems to imply that when VCC is 0, we get NO closed, and NC open?!

What I'm after, is that I want to know what the default state of the switch is without power applied, or if it always needs power to function. If this where a relais the answer would be obvious, but this being solid-state territory; I don't know.

I currently toggle the power to this switch and some other control logic via a mosfet, and while the consumption is probably irrelevant, I do want to know if I should keep the switch always powered.

[xvr]

Datasheet paragraph 10 (Power Supply Recommendations):

Always sequence VCC on first, followed by NO, NC, or COM.

Also, all Electrical Characteristics tables contains row:

COM, Vno, Vnc: Analog signal range: 0 - VCC

So when Vcc is 0 all input/output should be zero.

What I'm after, is that I want to know what the default state of the switch is without power applied, or if it always needs power to function.

Default state doesn't matter - output always will be 0

As I can guess this chip (as any other CMSO) has protection diodes to power rails on input/output, so when you turn off power (to high Z state) it will power itself from all NC/NO inputs (or COM, if it will be used as input)