Hi,
Onlooker has a great point. Lets do the math:
I would estimate as follows for brand name AA.
(SOC = state of charge)
At 50% SOC
V= 1.4, Battery ESR = 0.3 Ohms
Maximum Power Theorem, gives max power in load as
(V/2)2 / ESR = 1.6W
If you allow a conversion efficiency of 85% in the Batteriser
Max current at 50% SOC is 1.6W x 0.85/1.5V = 0.9A
At 20% SOC
V= 1V, ESR =0.6 Ohm
(V/2)2 / ESR = 0.42W
If you allow a conversion efficiency of 85% in the Batteriser
Max current at 50% SOC is 0.42W x 0.85/1.5V = 0.24A
Regards,
Jay_Diddy_B