Unless you provide a proper drawing of what you want to do, there is no way for anyone else to say if you need one per switch -- but most likely, you do.
As I tried to explain in the previous post, there is no voltage output, only an only a transistor with an open collector that turns on whenever the input voltage is above or below a certain threshold.
You need to supply the chip with ground and 5V (it can handle up to 20V). You also need a pullup resistor from the output (Vo) to 5V that makes the output stay high (logic "1") when the transistor is off. Once it turns on, the output will be grounded, and you get a low voltage (logic "0").
Now, the actual output of the HCPL3700 will rapidly turn on and off as the AC waveform goes through zero. If you are not prepared to handle that, you can either smooth it out with a rectifier and capacitor on the output, or use the other circuit which already has a capacitor on the input that should make the LED continue to work for the brief moment when there is a zero crossing.