There are at least 2 ways you can do this:
1) Use a standard SMD footprint for your device, and run two traces to each pad. This seems to be what anovice is suggesting. This is simple and has no assembly problems even on small resistors, but has the problem that the solder joint is included in the resistance. There is also a voltage gradient across the pad as the current moves towards the current trace, so the value you get depends exactly on how the sense lead comes in. This is fine for basic use, but is really inferior to any true 4 terminal connection.
2) Use two completely separate pads, and solder the resistor terminal to both of them. This is much better because you get the solder joint (mostly) out of the equation, but still has the same problem that there is a voltage drop across the terminal, and you are sensing the voltage at a single point. If the terminal has a significant fraction of the total resistance, your effective resistance depends on where the sense lead is connected. Take a look at that analog devices link that coppice posted -- the exact design of the pads make a pretty big difference. If the datasheet doesn't specify a 4 terminal layout (which cheap 2 terminal resistors don't normally do), then you can do your best, but you can't guarantee you get the best results.
In addition, the terminal material may not be the same as the resistive element, and therefore may not have the same temperature coefficient or aging performance as the main resistive element.
It all comes down to what level of accuracy and repeatability you need. A 4-terminal device lets the manufacturer control exactly where the sense leads are connected and make sure that it meets the datasheet performance when used that way.