I've been looking around at discrete transistors with built-in biasing resistors, and I came across this part:
http://www.mouser.com/ds/2/302/PIMN31-117357.pdfThese are dual NPN transistors with built-in biasing resistors. However, the configuration is one I've never seen before.
I've attached a screenshot of the internals taken from that datasheet.
This part has R1 (1kohm) in between the base of the transistor and the external pin, but then it has R2 (10kohm) directly connecting the base to the transistor's emitter.
I've never seen the base connected to the emitter through a resistor before in any biasing configuration I've ever come across. There's usually a separate emitter resistor, and a separate voltage divider on the base. Can someone explain what the purpose of this part is please?