You keep saying its a physics problem. Which law of physics does it break? Be specific, show us the math where a 1 G equation (gravity) fails to scale to 10000 G.
Are you suggesting that Newton's laws of motion are wrong? Law of Inertia? Force = mass times acceleration? Action and equal and opposite reaction?
Or perhaps Einsteins mass-energy relationship? E=mc^2?
Or maybe you're just using physics as a whipping horse, because you don't really understand physics?
It is the centrifugal G that is the problem. The 1g gravity has nothing to do with it. It is typical that these kinds of force is expressed in g so one can visualize the force in terms of "how many times it's own weight."
Evaluating using the launch's exit velocity, the centrifugal force is about 11,000g. 11,000g was evaluated using the initial (when this thread started) proposed launch velocity with a 100 meter diameter spinner. Launch velocity might have been increased since this tread started, this would mean even higher G.
Imagine you are standing on a merry-go-round that is turning, you will feel a force that tried to throw you off radially outward. That is the centrifugal G force. Gravity is still the same. If that merry-go-round is going so fast that it is generating 11,000g, it will tear itself apart. Assuming it is strong enough to hold itself together with you on it and your weight is 100 lb: Gravity is still 100 lb for you downward due to gravity, but the 11,000g centrifugal force means there will be a force of 1,100,000 lb pulling you off that merry-go-round radially outward away from the center of rotation. That huge (1.1 million lb) radially outward "weight" will crush a human body into jelly.
Unless you can break the Laws of Physics, you can't change that. A centrifugal force will be there whenever something spins.
For the object orbiting around a center, V is the linear velocity while orbiting, and it equals the velocity at release:
Centripetal /centrifugal acceleration is
a = V2/R, here R is the distance to the center of rotation.
To express that in number of G's, you divide it by normal gravity's acceleration which is 9.8m/s
2. (Meters per Second square)
At 11,000g, even the smallest of parts can self destruct when every thing is being pulled radially outward by 11000x it's own weight. This is the force that they cannot get around without breaking the laws of physics. To harden a payload to withstand that force will cost a bundle - this is what kills the economics of this launch method.
In an earlier reply on this thread, I did the math. If the clamp that holds the launch vehicle down (radially) had only a contact area of 6 square inch and the payload launch vehicle is 200kg, the radially outward pressure on it will be high enough to make diamond. So I had an earlier reply that shown the math, and joking that if I got that spinner, I will just spin a bucket of graphite with a 200kg cylinder of steel (cross section area of 6 square inch) sitting radially on it. I would make diamond rather than sell space launches.