gdewitte,
If you put it on the nA scale, it essentially is a 100X voltage amplifier with a 10k ohm input resistance. If that resistance is too low for you, you would have to remove the 10k shunt resistor.
Note that the maximum usable input voltage would be +/- 12.5mV, for which you would get a 1.25V output. Also note that if you want to get this full output swing even when the battery voltage starts to drop, your output load impedance should be quite high (100k ohm or more, which is true for current measurements as well).