Are you saying those 20nF capacitors are made of superconductor material ? Even the wires ?
Do you also have the means to cool them down to whatever temperature is needed to become superconductors ? You will not be able to use a mosfet switch in that case anyway.
FETs work fine at superconducting temperatures, just need the right ones.
The effect can be observed for superconducting wires (this need to include the switch and the capacitor plates). Unless you have access to some university lab with this sort of equipment I doubt this is an option for you.
You did not wired as shown in diagram as you added significant inductance connecting the super small 20nF capacitors with wires. There is no inductor drawn in the schematic for a good reason.
But you specifically requested superconductors; there is no resistance in the circuit. And it is, well,
wired -- I'm not sure where you suggest I go and get
noninductive wires from, I mean, that would be preposterous! ...Wouldn't it?
So I've done the nearest thing to the diagram I can do, and assumed the wire links mean wires, that, well, sometimes have inductance to them. I can't exactly help it, okay!
And yes you can not get rid of inductance or capacitance but when the diagram shows capacitors only you understand that inductance in that circuit will need to be negligibly small and that is not possible when you connect 20nF capacitors with wires.
Negligibly small in relation to......what?
It's not like there's an RC time constant in there. You said no resistance, I went to quite extreme lengths to eliminate it! But then what can be left?!
So use some few mF electrolytic capacitors and low power and efficient DC-DC converter as it is way easier and less expensive to setup than superconductors.
I also want to insist on the fact that I already proved multiple times with the correct equations that what I say is correct.
Main equation is the one for Energy stored in a capacitor = 0.5 * C * V2
Yes yes yes I get the refrain, if I
wanted perfect energy balance I could do that. But you don't understand, this isn't an application -- this is a curiosity. Surely you have a curiosity about this conundrum as well? -- Else, why stick in this thread so long?
Your claim that a sqrt(2) should pop up, is quite a curious one, and as a scientist, you should be as interested to disprove it, as I am to prove it! Yes, to disprove ones' own ideas, such a strange notion to some people, but it is the scientific method; there is none easier to fool than the self, as a famous scientist once said.
If you're curious, I reconstructed the experiment with much shorter, non-superconducting wires, and obtained this waveform:
It again does not show a sqrt(2) ratio, but shows the perfect 0.5 as predicted by charge balance. Energy is of course conserved because the excess is dissipated in the resistance, and no worries about whether the energy flowed around or through the wires, it got where it needed to go all the same.
Tim