Wikipedia has a brief reference to the first transatlantic telegraph cable and its poor performance mentioned in Veritasium's video:
https://en.wikipedia.org/wiki/Transmission_line#HistoryMathematical analysis of the behaviour of electrical transmission lines grew out of the work of James Clerk Maxwell, Lord Kelvin, and Oliver Heaviside. In 1855 Lord Kelvin formulated a diffusion model of the current in a submarine cable. The model correctly predicted the poor performance of the 1858 trans-Atlantic submarine telegraph cable. In 1885 Heaviside published the first papers that described his analysis of propagation in cables and the modern form of the telegrapher's equations.Kalvin's model, like most models, ignores the inductance of a straight wire. Understandable in a model because it isn't easy to determine and is usually negligible. Models aren't designed to handle 300,000km of zero resistance wire. They don't crop up much.
When two [electrically long] parallel wires are modeled as a transmission line, the transmission line model includes distributed inductance and capacitance of the wires. So, the inductance is there, it is not missing or ignored. The inductance is not negligible, because without this inductance there won't be a transmission line.
These kind of two-wire feedlines have been used by amateur radio operators over a hundred years, so the properties of these transmission lines are well known and understood. In practice their characteristic impedances are typically in range 300 ohm ... 600ohm, and their characteristic impedance is determined by the distance of the wires and the diameter of the wires. There is a lot of literature available for amateur radio operators on transmission lines.
It really doesn't matter how long a transmission line is when the transmission line can be considered as lossless. When the transmission line is lossless, the shape and amplitude of the traveling EM-field will remain unaltered. This is also true in practice for short, real-life coaxial cables, feed lines, PCB strip lines etc., and this can be easily verified with a step generator and an oscilloscope.
The transmission line model and its derivation can be found here:
https://en.wikipedia.org/wiki/Transmission_line#Telegrapher's_equationsThe characteristic impedance of a transmission line can be calculated as follows:
https://en.wikipedia.org/wiki/Twin-lead#Characteristic_impedanceHere are two online impedance calculators for parallel feed lines / transmission lines:
https://www.easycalculation.com/engineering/electrical/parallel-wire-impedance-calculator.phphttps://hamwaves.com/zc.circular/en/The first question that came to mind is where did the 12V come from to drive current through the 200 ohm load. Anyone who says capacitive coupling is welcome to calculate the capacitance per meter of two parallel wires a meter apart.
In this experiment, when the switch is closed, there will be two traveling steps of EM-field flowing along the two transmission lines (towards left from battery/switch/load and towards right from battery/switch/load), and the step-like shape of EM-fields will remain undistorted as the waves travel along the lossless wiring.
The current through the 200 ohm load [after 3.3ns when the switch is closed] is due to the circuit formed by a 12V battery, the two transmission lines and 200 ohm load. The characteristic impedance of the two wirings can be calculated, and the current can be calculated using Ohm's law (see my previous post above).
The transmission line model and the calculated characteristic impedance of the wires include the capacitance, too.
But yes there will be 12V, it comes from the tiny amount of shared magnetic flux as the current in the switched wire ramps up from zero to a few thousand amps, enough to create a few milliamps in the return wire.
After the switch is closed, there will not be a huge current surge in the wires. The current is limited by the wiring's characteristic impedance.