There's an interesting design feature that got missed.
That input op amp and JFET have just a +/- 5V supply, labelled +/- 5V(B), but the feedback loop is driven by that +/-100V voltage source. That means that the op amp input can see +/- 100V which is enough to release the magic smoke from any run-of-the-mill op amp.
So how's the magic smoke kept in? The +/- 5V(B) supply has its '0V' centre tap actually set by the output so it's not +/- 5V from ground, but +/- 5V from wherever the input is at, or to put it another way, the input amplifier supply is bootstrapped off the output. There are two reasons for doing this, firstly you couldn't find suitable JFETs that combined both low leakage and high voltage ratings, secondly it boosts the input impedance of the amplifier substantially.
Also, if you look carefully, that 250G resistor Dave mentioned as connected across the input isn't across the input, it's connected (via R337 at 2.2k) to a common rail labelled 'B', which is the bootstrap centre rail (or if you prefer, the composite amplifier output - see the 'B' connection near K301). That 250G is in parallel with the feedback loop, not across the input. That's the perils of a circuit diagram that defies convention and slaps the 250G feedback resistor down exactly where you'd conventionally draw a resistor that bridges the input.
Here's a, deliberately didactic, question for anyone who's interested in how this particular circuit works. What are R340 and R341 doing? They are respectively, 4.02k from the +5V(B) supply to the drains of the input JFET pair, and 402R from that junction to 'B'.