Read that old Tektronix reference about the different types of scope probe. A little research to understand what others have learned will save you from
repeating old mistakes and misunderstandings. Let's make
new mistakes
Others have a true 50ohm input, e.g.the Tektronix 485 which has both 1Mohm and 50ohm attenuators.
Your second picture shows a classic Z0 resistive divider probe, best used with a true 50ohm input.
Is the circuitry of a true 50 ohm input inherently less capacitive, perhaps fewer parts, shorter traces, etc? I am curious why the specs just say "50 ohm" not "50 ohm || 2pf" or something like that. It is almost as if it's implied that the capacitance is close to zero / negligible or is somehow compensated to be zero.
Nothing is perfect, but a competently implemented 50ohm attenuator will have a lot lower capacitance than 15pF.
But to make it more realistic, I first added 3pf of input capacitance and that resulted in BW=2Ghz.
Why is 3pF realistic, and more realistic than what?
In your simulations I will assume that your LTRA is 50ohm. Since a Z0 probe lead is only 1m long, I'd use a conventional lossless transmission line model. (You can't do that for the "high" impedance *10 probe, of course)
There is no reason to have the source R3 50ohm resistor in the simulation. In the special case where the source is 50ohms, you would connect it directly to the scope input. In most cases the source impedance won't be 50ohms; a typical logic gate (e.g. 74lvc1g*) has an output impedance in the 7ohms region.
C2 of 2pF is not reasonable for a Z0 probe. The 50yo HP10020 probes are "<0.7pF".
L1 of 15nH can be significantly reduced by the way the probe is connected to the UUT.