Hello forum members. I am very much confused...
So I have tablet and I want to drive it with 5v usb (stepping it down to 3V7-4V2).
Battery has protection board like one attached. Btw battery has only two wires (5v, GND), those are connected directly to protection board. GND thru FETS 5V to BAT+
With that board connected it works great. I supply 5v, and tablet powers on, without it tablet draws current, while pressing power button, but after release it stops.
But by looking at schematic of that protection board I do not understand how tablet "knows" about BPM (Battery Protection module).
What I have tested and thought of:
- Controller IC somehow communicates with charge IC thru 5v line (pulses?), tested via oscilloscope, no result. plain 5v line.
- FET1 and FET2 has body diodes, that might have voltage drop effecting how tablet sees this battery.
- R2 somehow pulls up/down to let charge ic in tablet know that it's ok to charge
I do understand how this circuit works and how two FETS are used to control charge/discharge, but how do tablet know about battery being in vs just plain 4.2v?..