Hello everyone,
I am using a simple voltage regulator MAX8881(
https://datasheets.maximintegrated.com/en/ds/MAX8880-MAX8881.pdf) for converting 9V to 5V for an ADC chip.
Unfortunately, I am not really sure about the wiring of the internal power-OK pin.
The full information about the pin is:
"The open-drain POK output is useful as a simple error flag, as well as a delayed reset output. POK sinks current when the output voltage is 10% below the regulation point. Connect POK to OUT through a high-value resistor for a simple error flag indicator. Connect a capacitor in parallel with the resistor to produce a delayed POK signal (delay set by the RC time constant). POK is low during out of regulation or in shutdown and is high impedance during normal operation."
Related to the description of the pin, I have three questions:
1. Can I just leave the pin not connected if I do not want to use this function? Or should I connect it to GND?
2. If I want to use it, what does a high-value resistor mean? 1K, 1 Mega ?
3. I am not really sure what "error flag" does mean? So if I connect the POK through a "high-value resistor" to the output, then if POK is "high," the voltage is stable, and I have 5V on the output. On the other hand, if POK is low, the output is also low, as it is connected to the ground. So can I consider the POK connected to the output as an AND gate?
4. I have a 9V supply from a battery, and I just want to keep the voltage power supply for an ADC on 5V stable. Should I use the POK in my case?
Thank you for considering my question!