So, a boost converter driven with constant frequency and duty cycle?
For Vo >> Vin / D, the inductor will fully discharge every cycle, i.e., operate in DCM (discontinuous conduction mode). That means every cycle, the inductor is charged to;
Starting with the inductor equation:
V = L dI/dt
V = V_in, dt = t_on, and L are given. Rearrange:
dI = V_in t_on / L
Initial current is zero, so dI is the peak current at turn-off.
The energy in the inductor is:
E = 0.5 L I^2
Substituting in I = dI,
E = 0.5 L (V t_on / L)^2
= 0.5 V_in^2 t_on^2 / L
This is delivered at F_sw pulses per second, or a power of
P = V_in^2 t_on^2 F_sw / L
The input current is I_in = P / V_in or
I_in = V_in t_on^2 F_sw / L
The input DC resistance is
R_in = V_in / I_in
= L / (t_on^2 F_sw)
Since D is given, I shouldn't have dragged along t_on; we can substitute t_on = D / F_sw, where D = 0.5 for this part.
R_in = L / (F_sw / (2 F_sw)^2) = L / (1 / (2 F_sw))
= 2 L F_sw
For 1mH and 32kHz, we get 65.5 ohms.
In general, we use a switching controller rather than a fixed oscillator, giving us a fully controllable R_in (typically, D is varied, or F_sw as well).
Note that a supply bypass capacitor is required. If the AC input current is dissipated by the TEG, lower efficiency will result. Simply enough, place a capacitor across the TEG, with value C >> 1 / (2 pi F_sw R_in), or, say, 100uF. Choose a low-ESR type (ESR << R_in).
Tim