@MarkF: Your trace is plotted at 5 V/div vertically, is this correct?
Also I am surprised that my Fast Edge result (2.35 ns risetime) is so much better than yours (3.20 ns), since my construction technique and connections are not as good as yours and I am using the HC version of the chip rather than the AC version. Is your scope unlocked to full bandwidth? (see my reply #14 above for the trace from my scope and FEO)
I had a 50Ω coax cable and 50Ω thru terminator connected from my PCB to the scope.
You need to ignore the vertical values.
The scope thinks it has a 10x probe connected instead of a 1:1 cable.
I didn't bother to change the vertical settings.
YES. My scope is an unlocked DS1074Z to 100MHz bandwidth.
If I'm thinking correctly here (i.e. a triangle waveform with these rise and fall times):
bandwidth = 1 / (rise_time + fall_time) = 1 / (3.2ns + 3.4ns) = 151MHz
as my measured bandwidth of the scope. Assuming, the edges are faster than the scope can measure.
By my same calculation:
Your 2.35ns rise time with the same fall time would result in a 212MHz bandwidth.
Are you summing four outputs or five? It looks like you amplitude is 500mV higher than mine.
I must be looking at this totally wrong???