In general, write down the currents into each node (there are 6 nodes plus ground). The currents are determined by the voltages on the two nodes each component connects between, and the transfer function of that component: I = V/R for the resistors and I = \$j \omega\C V$ for the capacitors. The op-amp and its feedback resistors can be treated as an ideal gain function, simplifying a few nodes (a more accurate model will treat it as an integrator, which in turn simplifies the area into a single pole transfer function). Finally, solve the matrix through whatever means you like -- you can do substitution and elimination by hand, or en masse via Gauss-Jordan elimination or whatever, or better yet (and more accurately), just cram it all into a CAS (computer algebra system) and crank out the result.
If that's too advanced, suggested reading is on op-amp circuit solutions, what assumptions and relations are used to do it; and on the basics of linear algebra, i.e. it's just a system of equations, and the rules for manipulating matrices and vectors are the same algebraic rules (hence linear algebra); that breaks things down to high school algebra levels.
Tim