quiescent current of opamp

[Jwillis]

On the OPA445 the quiescent current is typically ±4.2 mA . That means that the positive and negative will draw ±4.2mA with no load. How do I calculate the current at the supply pins under full load? Or am I over thinking this?
https://www.ti.com/lit/ds/symlink/opa445.pdf

[ledtester]

Starting with I_Q, just add the output current to the V+ current (if the output is sourcing current) or the V- current (if the output is sinking current).

So the max current through either the V+ or V- supply pin is i_Q + your max output current.

See also:

https://electronics.stackexchange.com/a/31032/95488

[Jwillis]

Wow! That easy? I thought it would be more complex. Just wanted to make sure a 1 amp -15V regulator at the negative side would be enough without a pass transistor.