I'm not familiar with this sort of calculation, so I'd appreciate someone letting me know if I'm "in the ballpark" here.
My garage door opener uses a standard 9v battery, and I measured the current (not transmitting) at 13 µA.
I couldn't find any discharge curves that low, but at 100 ma, the most batteries hit the cliff at about .35 ampere hours. (.30 - .45)
So, at 13 µA, that's .35/.000013 = approximately 27,000 hours. That seems like a long time, and that my current draw isn't a problem, but I can't help but believe I've made a mistake.
My other garage door opener's standby current is zero using the same meter, but it's a different brand. I'm not sure if that's relevant. It does make me think that 13 µA is too high.