Author Topic: How can I proportionally increase current draw from a load?  (Read 790 times)

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Offline doublec4Topic starter

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How can I proportionally increase current draw from a load?
« on: December 13, 2020, 06:59:54 am »
Hi all,

I have a powered RFID tag that consumes very little current (~2mA). I would like to use a high side current sensor to read the current... however the load of the RFID tag is low compared to the range of the current sensor (let's say 1-10mA).

Is there a way to proportionally increase the current draw from the RFID tag to somewhere closer to the middle of the sensor range, ie. 5mA ?

So when I say proportionally increase, for example if the RFID tag current drops to 1mA, the current being seen by the current sensor would also drop by 1/2 to 2.5mA

Hope this isn't a silly question! I know another option is to change the R_sense of the current sensing device but if possible I would not like to try and modify the surface mount part if I do not have to.

Thank you
 

Offline ledtester

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Re: How can I proportionally increase current draw from a load?
« Reply #1 on: December 13, 2020, 07:21:33 am »
How about use a current sensor with a programmable gain amplifier? For instance, the INA219 can be programmed for /1, /2, /4 or /8 gain.


Nice summary of current sense modules commonly used with microcontrollers:

https://youtu.be/cG8moaufmQs
« Last Edit: December 13, 2020, 07:24:08 am by ledtester »
 

Offline S. Petrukhin

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Re: How can I proportionally increase current draw from a load?
« Reply #2 on: December 13, 2020, 09:45:13 pm »
No amount of persuasion and arrangement can get more current consumption from RFID, you will have to change the circuit. Maybe you will be satisfied with a parallel shift of the current consumed to the sensor's sensitive area by simply installing a resistor in parallel with the RFID power?
And sorry for my English.
 

Offline David Hess

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Re: How can I proportionally increase current draw from a load?
« Reply #3 on: December 13, 2020, 11:14:01 pm »
Either offset the current by adding another fixed current through the current sensor or multiply the current, which can be done with a current mirror.
 


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