After watching Dave's
, I'm confused about the diode bridge used to clamp voltage across the shunts until the fuse blows.
Dave says the diode bridge in the Fluke 27 uses standard 1n4007 diodes, and indeed the
service manual confirms this. However, the 1n4007 diodes I've found can only handle a peek forward current of 30-45A for single digit milliseconds (
example 1,
example 2). Surely the current will be much higher than this if you plug your meter directly into mains? Until your mains breaker blows, you'd be limited just by the resistance of the fuse. I measured the 44/100A fuse in my Fluke 87 (same fuse as the 27) at ~800 mOhms. At 120V where I'm from, that's 150 amps.
How can the diodes deal with this huge amount of current for the amount of time it takes for the fuse to blow? I must be missing something.