Based on the 75%, it looks like the battery will only last around 650 cycles
This is why I want DOD 40%. To keep alive the battery for 3 year before replacing it (as 1 cycle per 1 day).
You plan to use 2.5*6 = 15Ah, so you're discharging about 75%.
I see more clearly now. Let do it again :
I want draw 2.5A during 6 hours.
the table show that I can draw
2.52A during
8h and after this time, the cut-off voltage will be at 1.75V/cell (10.5V).
2.52A during 8h give a rated capacity of 20,16Ah (this relation seem not to be linear in reality but whatever, see note *). With a 40%DOD, the usable energy is 20.16Ah * 40% = 8.064Ah
The supply time give now : t = 8.064Ah/2.5Ah = 3,22h =
3h13 !
Half time of my requirement ... Mmh
Does it seem correct ?
And how can I find the voltage level of my battery after drawing 8Ah ?
note *:
Rated capacity:
10hr, 1.80V/cell, 25°C 22AH/2.06A
5hr, 1.75V/cell, 25°C 18.0AH/3.6A
Which mean 10hr*2.06A = 20.6Ah ? 22Ah
But 5h*3.6A = 18Ah